30b^2+13b-3=0

Solution for 30b^2+13b-3=0 equation:

30b^2+13b-3=0

a = 30; b = 13; c = -3;
Δ = b2-4ac
Δ = 132-4·30·(-3)
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{529}=23$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-23}{2*30}=\frac{-36}{60}
=-3/5
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+23}{2*30}=\frac{10}{60}
=1/6
$